What is the axis (x^2)/(25)+((y+3)^2)/(49)=1 ?

The axis (x^2)/(25)+((y+3)^2)/(49)=1 is semi-major axis b=7, semi-minor axis a=5

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axis (x^2)/(25)+((y+3)^2)/(49)=1

axis

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

semi - major axis b = 7, semi - minor axis a = 5

Solution steps

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 3), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 3), b = 7, a = 5

\frac{( x - 2 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

x^{2} + 4 y^{2} = 16

What is the axis (x^2)/(25)+((y+3)^2)/(49)=1 ?
The axis (x^2)/(25)+((y+3)^2)/(49)=1 is semi-major axis b=7, semi-minor axis a=5