achse (x^2)/(25)+((y+3)^2)/(49)=1

Lösung

achse

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

semi - major axis b = 7, semi - minor axis a = 5

Schritte zur Lösung

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 3), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 3), b = 7, a = 5

a x i s \frac{( x - 2 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

a x i s \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

a x i s 4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

a x i s x^{2} + 4 y^{2} = 16

a x i s \frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1