What is the eccentricity (x^2)/(36)+(y^2)/(11)=1 ?

The eccentricity (x^2)/(36)+(y^2)/(11)=1 is 5/6

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eccentricity (x^2)/(36)+(y^2)/(11)=1

eccentricity

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

\frac{5}{6}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 11

= \frac{6 ^{2} - ( 11 ) ^{2}}{6}

\frac{6 ^{2} - ( 11 ) ^{2}}{6} = \frac{5}{6}

= \frac{5}{6}

4 x^{2} + 32 x + 25 y^{2} - 250 y + 589 = 0

\frac{x ^{2}}{9} + \frac{( y + 5 ) ^{2}}{25} = 1

4 y^{2} + 9 x^{2} = 36

2 x^{2} + 3 y^{2} + 4 x = 1

2 x^{2} + y^{2} = 10

What is the eccentricity (x^2)/(36)+(y^2)/(11)=1 ?
The eccentricity (x^2)/(36)+(y^2)/(11)=1 is 5/6