exzentrizität 4x^2+32x+25y^2-250y+589=0

Lösung

exzentrizität

4 x^{2} + 32 x + 25 y^{2} - 250 y + 589 = 0

\frac{21}{5}

Dezimale

0.91651 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

4 x^{2} + 32 x + 25 y^{2} - 250 y + 589 = 0 :

Ellipse with center

(h, k) = (- 4, 5), a = 5, b = 2

= \frac{5 ^{2} - 2 ^{2}}{5}

\frac{5 ^{2} - 2 ^{2}}{5} = \frac{21}{5}

= \frac{21}{5}

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{( y + 5 ) ^{2}}{25} = 1

ecce n t r i c i t y 4 y^{2} + 9 x^{2} = 36

ecce n t r i c i t y 2 x^{2} + 3 y^{2} + 4 x = 1

ecce n t r i c i t y 25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

ecce n t r i c i t y 18 x^{2} + 8 y^{2} + 36 x - 32 y - 22 = 0