What is the eccentricity 2x^2+7y^2=14 ?

The eccentricity 2x^2+7y^2=14 is sqrt(5/7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity 2x^2+7y^2=14

eccentricity

2 x^{2} + 7 y^{2} = 14

\frac{5}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

2 x^{2} + 7 y^{2} = 14 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 2

= \frac{( 7 ) ^{2} - ( 2 ) ^{2}}{7}

\frac{( 7 ) ^{2} - ( 2 ) ^{2}}{7} = \frac{5}{7}

= \frac{5}{7}

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

8 x^{2} + 2 y^{2} = 16

2 x^{2} + y^{2} - 8 y - 2 x + 1 = 0

What is the eccentricity 2x^2+7y^2=14 ?
The eccentricity 2x^2+7y^2=14 is sqrt(5/7)