What is the eccentricity 9x^2+7y^2=63 ?

The eccentricity 9x^2+7y^2=63 is (sqrt(2))/3

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eccentricity 9x^2+7y^2=63

eccentricity

9 x^{2} + 7 y^{2} = 63

\frac{2}{3}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

9 x^{2} + 7 y^{2} = 63 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 7

= \frac{3 ^{2} - ( 7 ) ^{2}}{3}

\frac{3 ^{2} - ( 7 ) ^{2}}{3} = \frac{2}{3}

= \frac{2}{3}

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

x^{2} + 16 y^{2} - 64 = 0

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

2 x^{2} + 7 y^{2} = 14

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

What is the eccentricity 9x^2+7y^2=63 ?
The eccentricity 9x^2+7y^2=63 is (sqrt(2))/3