What is the eccentricity (x^2)/(16)+(y^2)/(25)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(25)=1 is 3/5

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eccentricity (x^2)/(16)+(y^2)/(25)=1

eccentricity

\frac{3}{5}

Decimal

0.6

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 4

= \frac{5 ^{2} - 4 ^{2}}{5}

\frac{5 ^{2} - 4 ^{2}}{5} = \frac{3}{5}

= \frac{3}{5}

What is the eccentricity (x^2)/(16)+(y^2)/(25)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(25)=1 is 3/5