What is the eccentricity (x/8)^2+(y/6)^2=1 ?

The eccentricity (x/8)^2+(y/6)^2=1 is (sqrt(7))/4

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eccentricity (x/8)^2+(y/6)^2=1

eccentricity

\frac{7}{4}

Decimal

0.66143 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 6

= \frac{8 ^{2} - 6 ^{2}}{8}

\frac{8 ^{2} - 6 ^{2}}{8} = \frac{7}{4}

= \frac{7}{4}

What is the eccentricity (x/8)^2+(y/6)^2=1 ?
The eccentricity (x/8)^2+(y/6)^2=1 is (sqrt(7))/4