What is the eccentricity 5x^2+7y^2=35 ?

The eccentricity 5x^2+7y^2=35 is sqrt(2/7)

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eccentricity 5x^2+7y^2=35

eccentricity

5 x^{2} + 7 y^{2} = 35

\frac{2}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 35 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

= \frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7}

\frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7} = \frac{2}{7}

= \frac{2}{7}

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

x^{2} + 4 y^{2} - 16 = 0

36 x^{2} + 9 y^{2} = 324

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

What is the eccentricity 5x^2+7y^2=35 ?
The eccentricity 5x^2+7y^2=35 is sqrt(2/7)