What is the eccentricity 5x^2+7y^2=35 ?

The eccentricity 5x^2+7y^2=35 is sqrt(2/7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

eccentricity 5x^2+7y^2=35

eccentricity

\frac{2}{7}

Decimal

0.53452 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

5 x^{2} + 7 y^{2} = 35 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

= \frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7}

\frac{( 7 ) ^{2} - ( 5 ) ^{2}}{7} = \frac{2}{7}

= \frac{2}{7}

What is the eccentricity 5x^2+7y^2=35 ?
The eccentricity 5x^2+7y^2=35 is sqrt(2/7)