What is the eccentricity (x^2)/3+(y^2)/5 =1 ?

The eccentricity (x^2)/3+(y^2)/5 =1 is sqrt(2/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

eccentricity (x^2)/3+(y^2)/5 =1

eccentricity

\frac{2}{5}

Decimal

0.63245 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

= \frac{( 5 ) ^{2} - ( 3 ) ^{2}}{5}

\frac{( 5 ) ^{2} - ( 3 ) ^{2}}{5} = \frac{2}{5}

= \frac{2}{5}

What is the eccentricity (x^2)/3+(y^2)/5 =1 ?
The eccentricity (x^2)/3+(y^2)/5 =1 is sqrt(2/5)