What is the center x^2+9y^2-14x+36y+49=0 ?

The center x^2+9y^2-14x+36y+49=0 is (7,-2)

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center x^2+9y^2-14x+36y+49=0

center

(7, - 2)

Solution steps

x^{2} + 9 y^{2} - 14 x + 36 y + 49 = 0

Rewrite

x^{2} + 9 y^{2} - 14 x + 36 y + 49 = 0

in the form of the standard ellipse equation

\frac{( x - 7 ) ^{2}}{6 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (7, - 2), a = 6, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (7, - 2), a = 6, b = 2

And the center is:

(7, - 2)

What is the center x^2+9y^2-14x+36y+49=0 ?
The center x^2+9y^2-14x+36y+49=0 is (7,-2)