What is the center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 ?

The center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 is (1,1)

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center ((x-1)^2)/(36)+((y-1)^2)/(25)=1

center

\frac{( x - 1 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{25} = 1

(1, 1)

Solution steps

\frac{( x - 1 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{6 ^{2}} + \frac{( y - 1 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 1), a = 6, b = 5

And the center is:

(1, 1)

x^{2} + 4 y^{2} + 8 y = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

4 x^{2} + 9 y^{2} - 8 x - 36 y + 4 = 0

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{25} = 1

2 x^{2} + 2 y^{2} + 4 y = 0

What is the center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 ?
The center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 is (1,1)