What is the center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 ?

The center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 is (1,1)

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center ((x-1)^2)/(36)+((y-1)^2)/(25)=1

center

(1, 1)

Solution steps

\frac{( x - 1 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{6 ^{2}} + \frac{( y - 1 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 6, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 1), a = 6, b = 5

And the center is:

(1, 1)

What is the center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 ?
The center ((x-1)^2)/(36)+((y-1)^2)/(25)=1 is (1,1)