What is the center (x^2)/(63500)+(y^2)/(50900)=1 ?

The center (x^2)/(63500)+(y^2)/(50900)=1 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

center (x^2)/(63500)+(y^2)/(50900)=1

center

(0, 0)

Solution steps

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

Rewrite

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 10 635 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 10 509 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10635, b = 10509

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10635, b = 10509

And the center is:

(0, 0)

What is the center (x^2)/(63500)+(y^2)/(50900)=1 ?
The center (x^2)/(63500)+(y^2)/(50900)=1 is (0,0)