What is the center 4x^2+9y^2-24x+72y+144=0 ?

The center 4x^2+9y^2-24x+72y+144=0 is (3,-4)

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center 4x^2+9y^2-24x+72y+144=0

center

(3, - 4)

Solution steps

4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

Rewrite

4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, - 4), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (3, - 4), a = 3, b = 2

And the center is:

(3, - 4)

What is the center 4x^2+9y^2-24x+72y+144=0 ?
The center 4x^2+9y^2-24x+72y+144=0 is (3,-4)