What is the foci ((x)^2)/(46)+((y+8)^2)/(26)=1 ?

The foci ((x)^2)/(46)+((y+8)^2)/(26)=1 is (2sqrt(5),-8),(-2sqrt(5),-8)

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foci ((x)^2)/(46)+((y+8)^2)/(26)=1

foci

(25, - 8), (- 25, - 8)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{46} + \frac{( y + 8 ) ^{2}}{26} = 1 :

Ellipse with center

(h, k) = (0, - 8), a = 46, b = 26

(0 + c, - 8), (0 - c, - 8)

Compute

c :

c = 46^{2} - 26^{2} : 25

(0 + 25, - 8), (0 - 25, - 8)

Refine

(25, - 8), (- 25, - 8)

What is the foci ((x)^2)/(46)+((y+8)^2)/(26)=1 ?
The foci ((x)^2)/(46)+((y+8)^2)/(26)=1 is (2sqrt(5),-8),(-2sqrt(5),-8)