What is the foci ((x+1)^2}{3/2}+\frac{y^2)/1 =1 ?

The foci ((x+1)^2}{3/2}+\frac{y^2)/1 =1 is (-1+sqrt(1/2),0),(-1-sqrt(1/2),0)

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foci ((x+1)^2}{3/2}+\frac{y^2)/1 =1

foci

(- 1 + \frac{1}{2}, 0), (- 1 - \frac{1}{2}, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 1 ) ^{2}}{\frac{3}{2}} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (- 1, 0), a = \frac{3}{2}, b = 1

(- 1 + c, 0), (- 1 - c, 0)

Compute

c :

c = \frac{3}{2}^{2} - 1^{2} : \frac{1}{2}

(- 1 + \frac{1}{2}, 0), (- 1 - \frac{1}{2}, 0)

What is the foci ((x+1)^2}{3/2}+\frac{y^2)/1 =1 ?
The foci ((x+1)^2}{3/2}+\frac{y^2)/1 =1 is (-1+sqrt(1/2),0),(-1-sqrt(1/2),0)