{
"query": {
"display": "$$x^{2}-2x-4y+9=0$$",
"symbolab_question": "CONIC#x^{2}-2x-4y+9=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(1,2),p=1"
},
"steps": {
"type": "interim",
"title": "$$x^{2}-2x-4y+9=0:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(1,\\:2\\right),\\:$$and focal length $$|p|=1$$",
"input": "x^{2}-2x-4y+9=0",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$x^{2}-2x-4y+9=0\\:$$in the standard form",
"input": "x^{2}-2x-4y+9=0",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "4y=x^{2}-2x+9"
},
{
"type": "step",
"primary": "Divide by $$4$$",
"result": "y=\\frac{x^{2}}{4}-\\frac{x}{2}+\\frac{9}{4}"
},
{
"type": "interim",
"title": "Complete the square $$\\frac{x^{2}}{4}-\\frac{x}{2}+\\frac{9}{4}:{\\quad}\\frac{1}{4}\\left(x-1\\right)^{2}+2$$",
"input": "\\frac{x^{2}}{4}-\\frac{x}{2}+\\frac{9}{4}",
"steps": [
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c$$",
"result": "\\frac{1\\cdot\\:x^{2}}{4}-\\frac{x}{2}+\\frac{9}{4}"
},
{
"type": "step",
"primary": "Write $$\\frac{1x^{2}}{4}-\\frac{x}{2}+\\frac{9}{4}\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$\\frac{1}{4}$$"
],
"result": "\\frac{1}{4}\\left(x^{2}-2x+9\\right)"
},
{
"type": "interim",
"title": "$$2a=-2{\\quad:\\quad}a=-1$$",
"input": "2a=-2",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=-2",
"result": "a=-1",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{-2}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=-1"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(-1\\right)^{2}\\:$$",
"result": "\\frac{1}{4}\\left(x^{2}-2x+9+\\left(-1\\right)^{2}-\\left(-1\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}-2x+\\left(-1\\right)^{2}=\\left(x-1\\right)^{2}$$",
"Complete the square"
],
"result": "\\frac{1}{4}\\left(\\left(x-1\\right)^{2}+9-\\left(-1\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\frac{1}{4}\\left(x-1\\right)^{2}+2"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y=\\frac{1}{4}\\left(x-1\\right)^{2}+2"
},
{
"type": "step",
"primary": "Subtract $$2$$ from both sides",
"result": "y-2=\\frac{1}{4}\\left(x-1\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$\\frac{1}{4}$$",
"result": "4\\left(y-2\\right)=\\left(x-1\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\cdot\\:1\\cdot\\:\\left(y-2\\right)=\\left(x-1\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\cdot\\:1\\cdot\\:\\left(y-2\\right)=\\left(x-1\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(1,\\:2\\right),\\:p=1"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-1)^{2}}{4\\cdot 1}+2",
"displayFormula": "4\\cdot 1(y-2)=(x-1)^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=1",
"displayFormula": "y=1",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(1,2)",
"(1,3)"
],
"pointsDecimal": [
{
"fst": 1,
"snd": 2
},
{
"fst": 1,
"snd": 3
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot 1\\cdot (y-2)=(x-1)^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -10.25,
"xMax": 12.25,
"yMin": -9.25,
"yMax": 13.25
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is x^2-2x-4y+9=0 ?
The solution to x^2-2x-4y+9=0 is Parabola with (h,k)=(1,2),p=1