{
"query": {
"display": "$$y-x>-x^{2}-1$$",
"symbolab_question": "CONIC#y-x>-x^{2}-1"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "formula",
"default": "(h,k)=(\\frac{1}{2},-\\frac{3}{4}),p=-\\frac{1}{4}"
},
"steps": {
"type": "interim",
"title": "$$y-x>-x^{2}-1:\\quad$$Parabola with vertex at $$\\left(h,\\:k\\right)=\\left(\\frac{1}{2},\\:-\\frac{3}{4}\\right),\\:$$and focal length $$|p|=\\frac{1}{4}$$",
"input": "y-x>-x^{2}-1",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(y-k\\right)=\\left(x-h\\right)^{2}\\:$$ is the standard equation for an up-down facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$y-x>-x^{2}-1\\:$$in the standard form",
"input": "y-x>-x^{2}-1",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "y=-x^{2}+x-1"
},
{
"type": "interim",
"title": "Complete the square $$x-x^{2}-1:{\\quad}-\\left(x-\\frac{1}{2}\\right)^{2}-\\frac{3}{4}$$",
"input": "x-x^{2}-1",
"steps": [
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c$$",
"result": "-x^{2}+x-1"
},
{
"type": "step",
"primary": "Write $$-x^{2}+x-1\\:$$in the form: $$x^2+2ax+a^2$$",
"secondary": [
"Factor out $$-1$$"
],
"result": "-\\left(x^{2}-x+1\\right)"
},
{
"type": "interim",
"title": "$$2a=-1{\\quad:\\quad}a=-\\frac{1}{2}$$",
"input": "2a=-1",
"steps": [
{
"type": "interim",
"title": "Divide both sides by $$2$$",
"input": "2a=-1",
"result": "a=-\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{2a}{2}=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "a=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Add and subtract $$\\left(-\\frac{1}{2}\\right)^{2}\\:$$",
"result": "-\\left(x^{2}-x+1+\\left(-\\frac{1}{2}\\right)^{2}-\\left(-\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "$$x^2+2ax+a^2=\\left(x+a\\right)^2$$",
"secondary": [
"$$x^{2}-1x+\\left(-\\frac{1}{2}\\right)^{2}=\\left(x-\\frac{1}{2}\\right)^{2}$$",
"Complete the square"
],
"result": "-\\left(\\left(x-\\frac{1}{2}\\right)^{2}+1-\\left(-\\frac{1}{2}\\right)^{2}\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "-\\left(x-\\frac{1}{2}\\right)^{2}-\\frac{3}{4}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Complete Square 1Eq"
}
},
{
"type": "step",
"result": "y=-\\left(x-\\frac{1}{2}\\right)^{2}-\\frac{3}{4}"
},
{
"type": "step",
"primary": "Add $$\\frac{3}{4}$$ to both sides",
"result": "y+\\frac{3}{4}=-\\left(x-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$-1$$",
"result": "-\\left(y+\\frac{3}{4}\\right)=\\left(x-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(y-\\left(-\\frac{3}{4}\\right)\\right)=\\left(x-\\frac{1}{2}\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "4\\left(-\\frac{1}{4}\\right)\\left(y-\\left(-\\frac{3}{4}\\right)\\right)=\\left(x-\\frac{1}{2}\\right)^{2}"
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(\\frac{1}{2},\\:-\\frac{3}{4}\\right),\\:p=-\\frac{1}{4}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-\\frac{1}{2})^{2}}{4(-\\frac{1}{4})}-\\frac{3}{4}",
"displayFormula": "4(-\\frac{1}{4})(y-(-\\frac{3}{4}))=(x-\\frac{1}{2})^{2}",
"attributes": {
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"lineType": "DASH",
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},
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"evalFormula": "y=-\\frac{1}{2}",
"displayFormula": "y=-\\frac{1}{2}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
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"isAsymptote": false
}
}
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"pointsToDraw": {
"pointsLatex": [
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"snd": -1
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"attributes": [
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"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
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],
"labelColors": [
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},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
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],
"labelColors": [
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}
]
},
"fills": [
{
"ranges": [],
"funcIndices": [],
"funcs": [],
"xIneq": false,
"yIneq": false,
"twoVar": true,
"trueAboveLine": true,
"color": "rgba(171, 181, 235, 0.3)",
"func": "y=\\frac{(x-\\frac{1}{2})^{2}}{4(-\\frac{1}{4})}-\\frac{3}{4}"
}
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"functionChanges": [
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"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4(-\\frac{1}{4})(y-(-\\frac{3}{4}))>(x-\\frac{1}{2})^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
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"localBoundingBox": {
"xMin": -2.3125,
"xMax": 3.3125,
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}
Solution
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is y-x>-x^2-1 ?
The solution to y-x>-x^2-1 is Parabola with (h,k)=(1/2 ,-3/4),p=-1/4