{
"query": {
"display": "$$2x^{2}+y^{2}=2$$",
"symbolab_question": "CONIC#2x^{2}+y^{2}=2"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Ellipse",
"subTopic": "formula",
"default": "(h,k)=(0,0),a=1,b=\\sqrt{2}"
},
"steps": {
"type": "interim",
"title": "$$2x^{2}+y^{2}=2:{\\quad}$$Ellipse with center $$\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:b=\\sqrt{2},\\:a=1$$",
"input": "2x^{2}+y^{2}=2",
"steps": [
{
"type": "definition",
"title": "Ellipse standard equation",
"text": "$$\\frac{\\left(x-h\\right)^{2}}{a^2}+\\frac{\\left(y-k\\right)^{2}}{b^2}=1\\:$$is the ellipse standard equation<br/>with center $$\\left(h,\\:k\\right)\\:$$and $$a,\\:b$$ are the semi-major and semi-minor axes"
},
{
"type": "interim",
"title": "Rewrite $$2x^{2}+y^{2}=2\\:$$in the form of the standard ellipse equation",
"input": "2x^{2}+y^{2}=2",
"steps": [
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$2$$",
"result": "x^{2}+\\frac{1}{2}y^{2}=1"
},
{
"type": "step",
"primary": "Divide by coefficient of square terms: $$1$$",
"result": "\\frac{1}{1}x^{2}+\\frac{1}{2}y^{2}=1"
},
{
"type": "step",
"primary": "Refine",
"result": "\\frac{x^{2}}{1}+\\frac{y^{2}}{2}=1"
},
{
"type": "step",
"primary": "Rewrite in standard form",
"result": "\\frac{\\left(x-0\\right)^{2}}{1^{2}}+\\frac{\\left(y-0\\right)^{2}}{\\left(\\sqrt{2}\\right)^{2}}=1"
}
],
"meta": {
"interimType": "Ellipse Canonical Format 1Eq"
}
},
{
"type": "step",
"result": "\\frac{\\left(x-0\\right)^{2}}{1^{2}}+\\frac{\\left(y-0\\right)^{2}}{\\left(\\sqrt{2}\\right)^{2}}=1"
},
{
"type": "step",
"primary": "Therefore ellipse properties are:",
"result": "\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:a=1,\\:b=\\sqrt{2}"
},
{
"type": "step",
"primary": "$$b>a\\:$$therefore $$b\\:$$is semi-major axis and $$a\\:$$is semi-minor axis",
"result": "\\mathrm{Ellipse\\:with\\:center}\\:\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:b=\\sqrt{2},\\:a=1"
}
],
"meta": {
"solvingClass": "Ellipse"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{2(1-\\frac{x^{2}}{1^{2}})}",
"displayFormula": "\\frac{x^{2}}{1^{2}}+\\frac{y^{2}}{\\sqrt{2}^{2}}=1",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{2(1-\\frac{x^{2}}{1^{2}})}",
"displayFormula": "\\frac{x^{2}}{1^{2}}+\\frac{y^{2}}{\\sqrt{2}^{2}}=1",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{Center}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"linesToDraw": [
{
"p1x": "0",
"p1y": "0",
"p2x": "1",
"p2y": "0",
"attributes": {
"color": "GRAY",
"lineType": "BOLD",
"labels": [
"a=1"
],
"isAsymptote": false
}
},
{
"p1x": "0",
"p1y": "0",
"p2x": "0",
"p2y": "\\sqrt{2}",
"attributes": {
"color": "GRAY",
"lineType": "BOLD",
"labels": [
"b=\\sqrt{2}"
],
"isAsymptote": false
}
}
],
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "\\frac{x^{2}}{1^{2}}+\\frac{y^{2}}{(\\sqrt{2})^{2}}=1",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -3.1819805153394642,
"xMax": 3.1819805153394642,
"yMin": -3.1819805153394642,
"yMax": 3.1819805153394642
}
},
"showViewLarger": true
}
}
}
Solution
Solution
Solution steps
Rewrite in the form of the standard ellipse equation
Therefore ellipse properties are:
therefore is semi-major axis and is semi-minor axis
Graph
Popular Examples
(x-3)^2+y^2=4directrix y=-4x^2directrix vertices (x^2}{25}-\frac{y^2)/9 =1vertices x^2-2x-4y+9=04x^2+25y^2=100
Frequently Asked Questions (FAQ)
What is 2x^2+y^2=2 ?
The solution to 2x^2+y^2=2 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(2)