What is the vertices 9x^2+4y^2+36x-24y+36=0 ?

The vertices 9x^2+4y^2+36x-24y+36=0 is (-2,6),(-2,0)

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vertices 9x^2+4y^2+36x-24y+36=0

vertices

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

(- 2, 6), (- 2, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0 :

Ellipse with center

(h, k) = (- 2, 3), b = 3, a = 2

(- 2, 3 + 3), (- 2, 3 - 3)

Refine

(- 2, 6), (- 2, 0)

f (x) = 3 x^{2} - 18 x + 23

x^{2} + y^{2} \leq 25

2 x^{2} + y^{2} = 2

(x - 3)^{2} + y^{2} = 4

y = - 4 x^{2}

What is the vertices 9x^2+4y^2+36x-24y+36=0 ?
The vertices 9x^2+4y^2+36x-24y+36=0 is (-2,6),(-2,0)