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Popular >

vertices x^2+y^2-4y=0

Solution

vertices

x^{2} + y^{2} - 4 y = 0

Solution

(0, 4), (0, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

x^{2} + y^{2} - 4 y = 0 :

Ellipse with center

(h, k) = (0, 2), b = 2, a = 2

(0, 2 + 2), (0, 2 - 2)

Refine

(0, 4), (0, 0)

Popular Examples

vertices 9x^2-18x+4y^2=27 vertices

9 x^{2} - 18 x + 4 y^{2} = 27

vertices x^2+9y^2=9 vertices

x^{2} + 9 y^{2} = 9

vertices 4x^2+2y^2+2x-8y+7=0 vertices

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

vertices (x^2)/(16)+(y-4)^2=1 vertices

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

vertices 3x^2+y^2-24x+39=0 vertices

3 x^{2} + y^{2} - 24 x + 39 = 0

Frequently Asked Questions (FAQ)

What is the vertices x^2+y^2-4y=0 ?
The vertices x^2+y^2-4y=0 is (0,4),(0,0)