What is the vertices 9x^2-18x+4y^2=27 ?

The vertices 9x^2-18x+4y^2=27 is (1,3),(1,-3)

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vertices 9x^2-18x+4y^2=27

vertices

9 x^{2} - 18 x + 4 y^{2} = 27

(1, 3), (1, - 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} - 18 x + 4 y^{2} = 27 :

Ellipse with center

(h, k) = (1, 0), b = 3, a = 2

(1, 0 + 3), (1, 0 - 3)

Refine

(1, 3), (1, - 3)

x^{2} + 9 y^{2} = 9

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

3 x^{2} + y^{2} - 24 x + 39 = 0

25 x^{2} + 16 y^{2} = 400

What is the vertices 9x^2-18x+4y^2=27 ?
The vertices 9x^2-18x+4y^2=27 is (1,3),(1,-3)