What is ((1))/(x^2+y^2)=1 ?

The solution to ((1))/(x^2+y^2)=1 is Ellipse with (h,k)=(0,0),a=1,b=1

Popular >

((1))/(x^2+y^2)=1

\frac{( 1 )}{x ^{2} + y ^{2}} = 1

(h, k) = (0, 0), a = 1, b = 1

Solution steps

\frac{1}{x ^{2} + y ^{2}} = 1

Rewrite

\frac{1}{x ^{2} + y ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 1, a = 1

\frac{( x - 1 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{3} = 1

x^{2} - 4 y + y^{2} = 0

\frac{( x - 0 ) ^{2}}{25} + \frac{( y - 0 ) ^{2}}{2.25} = 1

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 8 ) ^{2}}{11} = 1

\frac{( x + 4 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{9} = 1

What is ((1))/(x^2+y^2)=1 ?
The solution to ((1))/(x^2+y^2)=1 is Ellipse with (h,k)=(0,0),a=1,b=1