What is ((x-5)^2)/(49)+((y-8)^2)/(11)=1 ?

The solution to ((x-5)^2)/(49)+((y-8)^2)/(11)=1 is Ellipse with (h,k)=(5,8),a=7,b=sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((x-5)^2)/(49)+((y-8)^2)/(11)=1

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 8 ) ^{2}}{11} = 1

(h, k) = (5, 8), a = 7, b = 11

Solution steps

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 8 ) ^{2}}{11} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{49} + \frac{( y - 8 ) ^{2}}{11} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{7 ^{2}} + \frac{( y - 8 ) ^{2}}{( 11 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, 8), a = 7, b = 11

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (5, 8), a = 7, b = 11

What is ((x-5)^2)/(49)+((y-8)^2)/(11)=1 ?
The solution to ((x-5)^2)/(49)+((y-8)^2)/(11)=1 is Ellipse with (h,k)=(5,8),a=7,b=sqrt(11)