What is 55x^2+5y^2=4 ?

The solution to 55x^2+5y^2=4 is Ellipse with (h,k)=(0,0),a= 2/(sqrt(55)),b= 2/(sqrt(5))

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55x^2+5y^2=4

55 x^{2} + 5 y^{2} = 4

(h, k) = (0, 0), a = \frac{2}{55}, b = \frac{2}{5}

Solution steps

55 x^{2} + 5 y^{2} = 4

Rewrite

55 x^{2} + 5 y^{2} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{2}{55} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{2}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{2}{55}, b = \frac{2}{5}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{2}{5}, a = \frac{2}{55}

What is 55x^2+5y^2=4 ?
The solution to 55x^2+5y^2=4 is Ellipse with (h,k)=(0,0),a= 2/(sqrt(55)),b= 2/(sqrt(5))