What is (x^2)/3+(y^2)/(sqrt(5))=1 ?

The solution to (x^2)/3+(y^2)/(sqrt(5))=1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=\sqrt[4]{5}

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(x^2)/3+(y^2)/(sqrt(5))=1

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

Solution steps

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

Rewrite

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

in the form of the standard ellipse equation

Therefore ellipse properties are:

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

0^{2} = (- 16 - x^{2} - y^{2})^{2}

150 = 60 x - 2 x^{2} + 80 y - 4 y^{2}

16 x^{2} + 25 y^{2} + 100 y = 300

25 x^{2} + 4 y^{2} - 50 x + 8 y - 71 = 0

16 x^{2} - 64 x + 25 y^{2} + 100 y = 236

What is (x^2)/3+(y^2)/(sqrt(5))=1 ?
The solution to (x^2)/3+(y^2)/(sqrt(5))=1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=\sqrt[4]{5}