What is 2x^2+y^2+4x-6y=7 ?

The solution to 2x^2+y^2+4x-6y=7 is Ellipse with (h,k)=(-1,3),a=3,b=3sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2x^2+y^2+4x-6y=7

2 x^{2} + y^{2} + 4 x - 6 y = 7

(h, k) = (- 1, 3), a = 3, b = 32

Solution steps

2 x^{2} + y^{2} + 4 x - 6 y = 7

Rewrite

2 x^{2} + y^{2} + 4 x - 6 y = 7

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} + \frac{( y - 3 ) ^{2}}{( 3 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 3), a = 3, b = 32

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 3), b = 32, a = 3

What is 2x^2+y^2+4x-6y=7 ?
The solution to 2x^2+y^2+4x-6y=7 is Ellipse with (h,k)=(-1,3),a=3,b=3sqrt(2)