What is 200=(1000)/(1+x^2+y^2) ?

The solution to 200=(1000)/(1+x^2+y^2) is Ellipse with (h,k)=(0,0),a=2,b=2

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200=(1000)/(1+x^2+y^2)

200 = \frac{1000}{1 + x ^{2} + y ^{2}}

(h, k) = (0, 0), a = 2, b = 2

Solution steps

200 = \frac{1000}{1 + x ^{2} + y ^{2}}

Rewrite

200 - \frac{1000}{1 + x ^{2} + y ^{2}} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 2

What is 200=(1000)/(1+x^2+y^2) ?
The solution to 200=(1000)/(1+x^2+y^2) is Ellipse with (h,k)=(0,0),a=2,b=2