What is 2x^2+2y^2-8y=0 ?

The solution to 2x^2+2y^2-8y=0 is Ellipse with (h,k)=(0,2),a=2,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

2x^2+2y^2-8y=0

2 x^{2} + 2 y^{2} - 8 y = 0

(h, k) = (0, 2), a = 2, b = 2

Solution steps

2 x^{2} + 2 y^{2} - 8 y = 0

Rewrite

2 x^{2} + 2 y^{2} - 8 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 2), b = 2, a = 2

What is 2x^2+2y^2-8y=0 ?
The solution to 2x^2+2y^2-8y=0 is Ellipse with (h,k)=(0,2),a=2,b=2