What is (((x+2)^2)/(25))+(((y-1)^2)/(169))=1 ?

The solution to (((x+2)^2)/(25))+(((y-1)^2)/(169))=1 is Ellipse with (h,k)=(-2,1),a=5,b=13

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(((x+2)^2)/(25))+(((y-1)^2)/(169))=1

(\frac{( x + 2 ) ^{2}}{25}) + (\frac{( y - 1 ) ^{2}}{169}) = 1

(h, k) = (- 2, 1), a = 5, b = 13

Solution steps

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{169} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{169} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{5 ^{2}} + \frac{( y - 1 ) ^{2}}{1 3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 1), a = 5, b = 13

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 1), b = 13, a = 5

What is (((x+2)^2)/(25))+(((y-1)^2)/(169))=1 ?
The solution to (((x+2)^2)/(25))+(((y-1)^2)/(169))=1 is Ellipse with (h,k)=(-2,1),a=5,b=13