What is 5y^2+4x^2= 5/4 ?

The solution to 5y^2+4x^2= 5/4 is Ellipse with (h,k)=(0,0),a=(sqrt(5))/4 ,b= 1/2

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5y^2+4x^2= 5/4

5 y^{2} + 4 x^{2} = \frac{5}{4}

(h, k) = (0, 0), a = \frac{5}{4}, b = \frac{1}{2}

Solution steps

5 y^{2} + 4 x^{2} = \frac{5}{4}

Rewrite

5 y^{2} + 4 x^{2} = \frac{5}{4}

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{4} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{4}, b = \frac{1}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{5}{4}, b = \frac{1}{2}

What is 5y^2+4x^2= 5/4 ?
The solution to 5y^2+4x^2= 5/4 is Ellipse with (h,k)=(0,0),a=(sqrt(5))/4 ,b= 1/2