What is 9x^2+25y^2+108x-200y+4=0 ?

The solution to 9x^2+25y^2+108x-200y+4=0 is Ellipse with (h,k)=(-6,4),a=4sqrt(5),b=(12)/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

9x^2+25y^2+108x-200y+4=0

9 x^{2} + 25 y^{2} + 108 x - 200 y + 4 = 0

(h, k) = (- 6, 4), a = 45, b = \frac{12}{5}

Solution steps

9 x^{2} + 25 y^{2} + 108 x - 200 y + 4 = 0

Rewrite

9 x^{2} + 25 y^{2} + 108 x - 200 y + 4 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 6 ) ) ^{2}}{( 4 5 ) ^{2}} + \frac{( y - 4 ) ^{2}}{( \frac{12}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 6, 4), a = 45, b = \frac{12}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 6, 4), a = 45, b = \frac{12}{5}

What is 9x^2+25y^2+108x-200y+4=0 ?
The solution to 9x^2+25y^2+108x-200y+4=0 is Ellipse with (h,k)=(-6,4),a=4sqrt(5),b=(12)/(sqrt(5))