What is y^2=-4x^2+16 ?

The solution to y^2=-4x^2+16 is Ellipse with (h,k)=(0,0),a=2,b=4

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y^2=-4x^2+16

y^{2} = - 4 x^{2} + 16

(h, k) = (0, 0), a = 2, b = 4

Solution steps

y^{2} = - 4 x^{2} + 16

Rewrite

y^{2} = - 4 x^{2} + 16

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

What is y^2=-4x^2+16 ?
The solution to y^2=-4x^2+16 is Ellipse with (h,k)=(0,0),a=2,b=4