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Popular >

x^2+y^2<2y

Solution

x^{2} + y^{2} < 2 y

Solution

(h, k) = (0, 1), a = 1, b = 1

Solution steps

x^{2} + y^{2} < 2 y

Rewrite

x^{2} + y^{2} < 2 y

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 1, a = 1

Popular Examples

25 x^{2} + 50 y^{2} = 25

(4x^2)/(25)+(9y^2)/(25)=1

\frac{4 x ^{2}}{25} + \frac{9 y ^{2}}{25} = 1

X^{2} + 8 Y^{2} - 5 = 0

((x-2)^2}{12}+\frac{(y+5)^2)/8 =1

\frac{( x - 2 ) ^{2}}{12} + \frac{( y + 5 ) ^{2}}{8} = 1

(y+2)^2=1-2(x+1)^2

(y + 2)^{2} = 1 - 2 (x + 1)^{2}

Frequently Asked Questions (FAQ)

What is x^2+y^2<2y ?
The solution to x^2+y^2<2y is Ellipse with (h,k)=(0,1),a=1,b=1