What is (4x^2)/(25)+(9y^2)/(25)=1 ?

The solution to (4x^2)/(25)+(9y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a= 5/2 ,b= 5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(4x^2)/(25)+(9y^2)/(25)=1

\frac{4 x ^{2}}{25} + \frac{9 y ^{2}}{25} = 1

(h, k) = (0, 0), a = \frac{5}{2}, b = \frac{5}{3}

Solution steps

\frac{4 x ^{2}}{25} + \frac{9 y ^{2}}{25} = 1

Rewrite

\frac{4 x ^{2}}{25} + \frac{9 y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{5}{2}, b = \frac{5}{3}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{5}{2}, b = \frac{5}{3}

What is (4x^2)/(25)+(9y^2)/(25)=1 ?
The solution to (4x^2)/(25)+(9y^2)/(25)=1 is Ellipse with (h,k)=(0,0),a= 5/2 ,b= 5/3