What is ((x+3)^2)/(64)+((y-6)^2)/(100)=1 ?

The solution to ((x+3)^2)/(64)+((y-6)^2)/(100)=1 is Ellipse with (h,k)=(-3,6),a=8,b=10

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((x+3)^2)/(64)+((y-6)^2)/(100)=1

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

(h, k) = (- 3, 6), a = 8, b = 10

Solution steps

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{8 ^{2}} + \frac{( y - 6 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 6), a = 8, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, 6), b = 10, a = 8

What is ((x+3)^2)/(64)+((y-6)^2)/(100)=1 ?
The solution to ((x+3)^2)/(64)+((y-6)^2)/(100)=1 is Ellipse with (h,k)=(-3,6),a=8,b=10