What is -2=(2x)/(x^2+y^2) ?

The solution to -2=(2x)/(x^2+y^2) is Ellipse with (h,k)=(-1/2 ,0),a= 1/2 ,b= 1/2

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-2=(2x)/(x^2+y^2)

- 2 = \frac{2 x}{x ^{2} + y ^{2}}

(h, k) = (- \frac{1}{2}, 0), a = \frac{1}{2}, b = \frac{1}{2}

Solution steps

- 2 = \frac{2 x}{x ^{2} + y ^{2}}

Rewrite

- 2 - \frac{2 x}{x ^{2} + y ^{2}} = 0

in the form of the standard ellipse equation

\frac{( x - ( - \frac{1}{2} ) ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- \frac{1}{2}, 0), a = \frac{1}{2}, b = \frac{1}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- \frac{1}{2}, 0), b = \frac{1}{2}, a = \frac{1}{2}

16 - x^{2} - 9 y^{2} > 0

9 x^{2} + 7 y^{2} = 1

8 x^{2} - 96 x + 18 y^{2} + 144 y + 288 = 0

2 x^{2} + 49 y^{2} = 98

4 x^{2} + 9 y^{2} - 40 x + 54 y + 1 + 5 = 0

What is -2=(2x)/(x^2+y^2) ?
The solution to -2=(2x)/(x^2+y^2) is Ellipse with (h,k)=(-1/2 ,0),a= 1/2 ,b= 1/2