x^2=4y+4

Lösung

x^{2} = 4 y + 4

(h, k) = (0, - 1), p = 1

Schritte zur Lösung

x^{2} = 4 y + 4

Rewrite

x^{2} = 4 y + 4

in the standard form:

4 \cdot 1 \cdot (y - (- 1)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = 1