2y^2-3y+3x=0

Lösung

2 y^{2} - 3 y + 3 x = 0

(h, k) = (\frac{3}{8}, \frac{3}{4}), p = - \frac{3}{8}

Schritte zur Lösung

2 y^{2} - 3 y + 3 x = 0

Rewrite

2 y^{2} - 3 y + 3 x = 0

in the standard form

4 (- \frac{3}{8}) (x - \frac{3}{8}) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{8}, \frac{3}{4}), p = - \frac{3}{8}