What is ((x-1)^2)/(7^2)+((y-1)^2)/(3^2)=1 ?

The solution to ((x-1)^2)/(7^2)+((y-1)^2)/(3^2)=1 is Ellipse with (h,k)=(1,1),a=7,b=3

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((x-1)^2)/(7^2)+((y-1)^2)/(3^2)=1

\frac{( x - 1 ) ^{2}}{7 ^{2}} + \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

(h, k) = (1, 1), a = 7, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{7 ^{2}} + \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 1), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 1), a = 7, b = 3

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{25} = 1

4 x^{2} + y^{2} - 8 x + 4 y - 4 = 0

x^{2} + 4 y^{2} - 6 x - 16 y + 21 > 0

\frac{x ^{2}}{2} + y^{2} = 2

\frac{( x - 2 ) ^{2}}{2} + \frac{( y - 1 ) ^{2}}{8} = 1

What is ((x-1)^2)/(7^2)+((y-1)^2)/(3^2)=1 ?
The solution to ((x-1)^2)/(7^2)+((y-1)^2)/(3^2)=1 is Ellipse with (h,k)=(1,1),a=7,b=3