What is 1/2 = x/((x^2+y^2)) ?

The solution to 1/2 = x/((x^2+y^2)) is Ellipse with (h,k)=(1,0),a=1,b=1

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1/2 = x/((x^2+y^2))

\frac{1}{2} = \frac{x}{( x ^{2} + y ^{2} )}

(h, k) = (1, 0), a = 1, b = 1

Solution steps

\frac{1}{2} = \frac{x}{x ^{2} + y ^{2}}

Rewrite

\frac{1}{2} - \frac{x}{x ^{2} + y ^{2}} = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 0), b = 1, a = 1

\frac{X ^{2}}{27} + \frac{Y ^{2}}{36} = 1

x^{2} - 10 x + 4 y^{2} - 8 y = 5

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{5} = 1

\frac{x ^{2}}{2} + \frac{y ^{2}}{3} = 1

9 x^{2} + y^{2} + 18 x + 2 y + 1 = 0

What is 1/2 = x/((x^2+y^2)) ?
The solution to 1/2 = x/((x^2+y^2)) is Ellipse with (h,k)=(1,0),a=1,b=1