What is 20x^2+40y^2=800 ?

The solution to 20x^2+40y^2=800 is Ellipse with (h,k)=(0,0),a=2sqrt(10),b=2sqrt(5)

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20x^2+40y^2=800

20 x^{2} + 40 y^{2} = 800

(h, k) = (0, 0), a = 210, b = 25

Solution steps

20 x^{2} + 40 y^{2} = 800

Rewrite

20 x^{2} + 40 y^{2} = 800

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 10 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 210, b = 25

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 210, b = 25

What is 20x^2+40y^2=800 ?
The solution to 20x^2+40y^2=800 is Ellipse with (h,k)=(0,0),a=2sqrt(10),b=2sqrt(5)