What is (x^2)/1+(y^2)/5 =1 ?

The solution to (x^2)/1+(y^2)/5 =1 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(5)

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(x^2)/1+(y^2)/5 =1

\frac{x ^{2}}{1} + \frac{y ^{2}}{5} = 1

(h, k) = (0, 0), a = 1, b = 5

Solution steps

\frac{x ^{2}}{1} + \frac{y ^{2}}{5} = 1

Rewrite

\frac{x ^{2}}{1} + \frac{y ^{2}}{5} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 1

4 x^{2} + y^{2} + 56 = 4 y - 56 x

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 6 ) ^{2}}{100} = 1

\frac{( x - ( - 2 ) ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

(\frac{x ^{2}}{15}) + (\frac{( y - 8 ) ^{2}}{49}) = 1

20 x^{2} + 40 y^{2} = 800

What is (x^2)/1+(y^2)/5 =1 ?
The solution to (x^2)/1+(y^2)/5 =1 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(5)