What is ((x+2)^2)/(64)+((y-1)^2)/(81)=1 ?

The solution to ((x+2)^2)/(64)+((y-1)^2)/(81)=1 is Ellipse with (h,k)=(-2,1),a=8,b=9

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((x+2)^2)/(64)+((y-1)^2)/(81)=1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

(h, k) = (- 2, 1), a = 8, b = 9

Solution steps

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{8 ^{2}} + \frac{( y - 1 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 1), a = 8, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 1), b = 9, a = 8

What is ((x+2)^2)/(64)+((y-1)^2)/(81)=1 ?
The solution to ((x+2)^2)/(64)+((y-1)^2)/(81)=1 is Ellipse with (h,k)=(-2,1),a=8,b=9