What is ((x^2}{25})+(\frac{y^2)/9)=1 ?

The solution to ((x^2}{25})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(0,0),a=5,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x^2}{25})+(\frac{y^2)/9)=1

(\frac{x ^{2}}{25}) + (\frac{y ^{2}}{9}) = 1

(h, k) = (0, 0), a = 5, b = 3

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 3

8 x^{2} + 16 x + 4 y^{2} - 12 y = 15

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{9} = 1

\frac{x ^{2}}{400} + \frac{y ^{2}}{256} = 1

3 x^{2} + y^{2} - 25 = 0

3 x^{2} + 12 y^{2} + 6 x - 24 y + 6 = 0

What is ((x^2}{25})+(\frac{y^2)/9)=1 ?
The solution to ((x^2}{25})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(0,0),a=5,b=3