en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2=-12y

Solution

foci

x^{2} = - 12 y

Solution

(0, - 3)

Solution steps

Rewrite

x^{2} = - 12 y

in the standard form:

4 (- 3) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 3

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + (- 3))

Refine

(0, - 3)

Popular Examples

vertices f(x)=x^2+6x+8 vertices

f (x) = x^{2} + 6 x + 8

4x^2+16y^2-4x-32y+1=0

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

x = (y + 2)^{2}

eccentricity x^2-y^2=4 eccentricity

x^{2} - y^{2} = 4

vertices f(x)=x^2+5x+6 vertices

f (x) = x^{2} + 5 x + 6

Frequently Asked Questions (FAQ)

What is the foci x^2=-12y ?
The foci x^2=-12y is (0,-3)