x=(y+2)^2

Solution

x = (y + 2)^{2}

(h, k) = (0, - 2), p = \frac{1}{4}

Solution steps

x = (y + 2)^{2}

Rewrite

x = (y + 2)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = \frac{1}{4}

x^{2} - y^{2} = 4

f (x) = x^{2} + 5 x + 6

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{25} = 1

x^{2} + y^{2} - 2 y = 0

What is x=(y+2)^2 ?
The solution to x=(y+2)^2 is Parabola with (h,k)=(0,-2),p= 1/4