kreisumfang x^2+y^2+6x-4y-51=0

Lösung

kreisumfang

x^{2} + y^{2} + 6 x - 4 y - 51 = 0

C = 16 π

Schritte zur Lösung

C = 2 π r

Finde den Radius

Radius given

x^{2} + y^{2} + 6 x - 4 y - 51 = 0 : r = 8

C = 2 π 8

Fasse zusammen

C = 16 π

c i rc u m f ere n ce x^{2} + y^{2} - 4 x - 12 = 0

c i rc u m f ere n ce 4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0

c i rc u m f ere n ce x^{2} + 14 x + y^{2} - 6 y - 23 = 0

c i rc u m f ere n ce 9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

c i rc u m f ere n ce (x - 3)^{2} + (y - 2)^{2} = 9