kreisumfang 4x^2+4y^2+28x-28y-24=0

Lösung

kreisumfang

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0

C = 2 π \frac{61}{2}

Schritte zur Lösung

C = 2 π r

Finde den Radius

Radius given

4 x^{2} + 4 y^{2} + 28 x - 28 y - 24 = 0 : r = \frac{61}{2}

C = 2 π \frac{61}{2}

c i rc u m f ere n ce x^{2} + 14 x + y^{2} - 6 y - 23 = 0

c i rc u m f ere n ce 9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

c i rc u m f ere n ce (x - 3)^{2} + (y - 2)^{2} = 9

c i rc u m f ere n ce x^{2} + 8 x - 6 y + y^{2} - 11 = 0

c i rc u m f ere n ce (x - (- 1))^{2} + (y - 2)^{2} = 6^{2}