What is the radius x^2+y^2-2x+2y-7=0 ?

The radius x^2+y^2-2x+2y-7=0 is r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

radius x^2+y^2-2x+2y-7=0

radius

r = 3

Solution steps

x^{2} + y^{2} - 2 x + 2 y - 7 = 0

Rewrite

x^{2} + y^{2} - 2 x + 2 y - 7 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 3

And the radius is:

r = 3