What is the radius x^2+y^2+6x+5y=-45/4 ?

The radius x^2+y^2+6x+5y=-45/4 is r=2

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radius x^2+y^2+6x+5y=-45/4

radius

r = 2

Solution steps

x^{2} + y^{2} + 6 x + 5 y = - \frac{45}{4}

Rewrite

x^{2} + y^{2} + 6 x + 5 y = - \frac{45}{4}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- \frac{5}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 3, - \frac{5}{2}), r = 2

And the radius is:

r = 2